7x*x=17^2

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Solution for 7x*x=17^2 equation:



7x*x=17^2
We move all terms to the left:
7x*x-(17^2)=0
We add all the numbers together, and all the variables
7x*x-289=0
Wy multiply elements
7x^2-289=0
a = 7; b = 0; c = -289;
Δ = b2-4ac
Δ = 02-4·7·(-289)
Δ = 8092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{8092}=\sqrt{1156*7}=\sqrt{1156}*\sqrt{7}=34\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34\sqrt{7}}{2*7}=\frac{0-34\sqrt{7}}{14} =-\frac{34\sqrt{7}}{14} =-\frac{17\sqrt{7}}{7} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34\sqrt{7}}{2*7}=\frac{0+34\sqrt{7}}{14} =\frac{34\sqrt{7}}{14} =\frac{17\sqrt{7}}{7} $

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